Current, Resistance and Ohms Law - Circuit Analysis Techniques

⏱ Time: 0s

Q1. What is the equivalent resistance of two resistors, R1 = 6Ω and R2 = 3Ω, connected in series?

Solution:

In series, the equivalent resistance is R_eq = R1 + R2 = 6Ω + 3Ω = 9Ω.

⏱ Time: 0s

Q2. If a capacitor has a capacitance of 10μF and is charged to a voltage of 5V, what is the charge stored in the capacitor?

Solution:

The charge stored in a capacitor is given by Q = C * V = 10μF * 5V = 50μC.

⏱ Time: 0s

Q3. In a circuit with a 12V battery and two resistors in series (4Ω and 8Ω), what is the voltage drop across the 8Ω resistor?

Solution:

Total resistance = 4Ω + 8Ω = 12Ω. Current I = V / R = 12V / 12Ω = 1A. Voltage drop across 8Ω = I * R = 1A * 8Ω = 8V.

⏱ Time: 0s

Q4. What is the total capacitance of two capacitors, C1 = 4μF and C2 = 6μF, connected in series?

Solution:

For capacitors in series, 1/C_eq = 1/C1 + 1/C2, so 1/C_eq = 1/4 + 1/6 = 5/12, thus C_eq = 2.4μF.

⏱ Time: 0s

Q5. What is the power dissipated by a 10Ω resistor carrying a current of 3A?

Solution:

Power (P) is given by P = I^2 * R = (3A)^2 * 10Ω = 90W.

⏱ Time: 0s

Q6. What is the electric field (E) at a distance of 2m from a point charge of 10μC?

Solution:

Using Coulomb's law, E = k * |Q| / r^2 = (8.99 x 10^9 N m²/C²) * (10 x 10^-6 C) / (2 m)^2 = 2247.5 N/C, approximately 2250 N/C.

⏱ Time: 0s

Q7. If a circuit has a total resistance of 10Ω and a current of 5A, what is the voltage across the circuit?

Solution:

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

⏱ Time: 0s

Q8. In a circuit with a 24V battery and a total resistance of 6Ω, what is the total current flowing through the circuit?

Solution:

Using Ohm's Law, I = V / R = 24V / 6Ω = 4A.

⏱ Time: 0s

Q9. In a simple series circuit with a 12V battery and two resistors (4Ω and 8Ω), what is the total current flowing through the circuit?

Solution:

Total resistance R_total = R1 + R2 = 4Ω + 8Ω = 12Ω. Using Ohm's Law, I = V / R_total = 12V / 12Ω = 1A.

⏱ Time: 0s

Q10. If a capacitor has a capacitance of 5μF and is charged to a voltage of 10V, what is the charge stored in the capacitor?

Solution:

Charge (Q) is given by Q = C * V = 5μF * 10V = 0.05C.