Current, Resistance and Ohms Law

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Q1. In a parallel circuit with a 12 V supply, what is the voltage across each resistor?

Solution:

In a parallel circuit, the voltage across each component is equal to the supply voltage, so it is 12 V.

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Q2. What is the total resistance of three resistors of 2 Ω, 3 Ω, and 5 Ω connected in series?

Solution:

In series, R_total = R1 + R2 + R3 = 2 Ω + 3 Ω + 5 Ω = 10 Ω.

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Q3. What is the equivalent capacitance of two capacitors of 4 µF and 6 µF connected in series?

Solution:

1/C_total = 1/C1 + 1/C2 = 1/4 µF + 1/6 µF = 1.2 µF, so C_total = 2.4 µF.

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Q4. What is the current through a 10 Ω resistor if the voltage across it is 30 V?

Solution:

Using Ohm's Law: I = V/R = 30 V / 10 Ω = 3 A.

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Q5. If a circuit has a voltage of 12 V and a resistance of 4 Ω, what is the current flowing through the circuit?

Solution:

Using Ohm's Law, I = V/R = 12 V / 4 Ω = 3 A.

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Q6. If a capacitor of 5 µF is charged to a voltage of 10 V, what is the charge stored in the capacitor?

Solution:

Charge (Q) = C * V = 5 µF * 10 V = 50 µC.

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Q7. What is the power dissipated in a resistor of 8 Ω carrying a current of 2 A?

Solution:

Power (P) = I^2 * R = (2 A)^2 * 8 Ω = 16 W.

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Q8. What is the energy stored in a capacitor of 4 µF charged to a voltage of 12 V?

Solution:

Using the formula U = 1/2 * C * V^2 = 1/2 * 4 x 10^-6 F * (12 V)^2 = 0.288 mJ.

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Q9. In a circuit with a 12 V battery and a resistor of 4 Ω, what is the current flowing through the circuit?

Solution:

Using Ohm's Law: I = V/R = 12 V / 4 Ω = 3 A.

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Q10. What is the capacitance of a capacitor that stores 0.01 C of charge at a voltage of 5 V?

Solution:

Using the formula C = Q/V = 0.01 C / 5 V = 0.002 F.