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Q1. In a parallel circuit with a 12 V battery, what is the voltage across each branch?
Solution:
In a parallel circuit, the voltage across each branch is equal to the source voltage, which is 12 V.
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Q2. If a resistor of 10 Ω is connected in series with a 5 Ω resistor, what is the total resistance?
Solution:
Total resistance in series is R_total = R1 + R2 = 10 Ω + 5 Ω = 15 Ω.
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Q3. What is the electric field strength at a distance of 0.2 m from a point charge of +5 µC?
Solution:
E = k * |q| / r^2 = (8.99 x 10^9 N m²/C²) * (5 x 10^-6 C) / (0.2 m)^2 = 112.5 N/C.
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Q4. In a series RC circuit, what happens to the current as the capacitor charges?
Solution:
As the capacitor charges, the current decreases exponentially until it approaches zero.
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Q5. What is the potential difference across a 20 Ω resistor carrying a current of 2 A?
Solution:
Using Ohm's law, V = I * R = 2 A * 20 Ω = 40 V.
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Q6. In an RC circuit, what is the time constant if R = 4 kΩ and C = 10 µF?
Solution:
Time constant τ = R * C = 4000 Ω * 10 x 10^-6 F = 40 ms.
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Q7. What is the electric potential energy of a system of two charges, +1 µC and -1 µC, separated by 0.1 m?
Solution:
Potential energy U = k * q1 * q2 / r = (8.99 x 10^9 N m²/C²) * (1 x 10^-6 C) * (-1 x 10^-6 C) / 0.1 m = -0.09 J.
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Q8. If a 10 V battery is connected to a 5 Ω resistor, what is the current flowing through the resistor?
Solution:
Using Ohm's law, I = V/R = 10 V / 5 Ω = 2 A.
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Q9. What is the electric potential energy of a system of two charges of +1 µC and -1 µC separated by 0.1 m?
Solution:
Potential energy U = k * q1 * q2 / r = (8.99 x 10^9 N m²/C²) * (1 x 10^-6 C) * (-1 x 10^-6 C) / 0.1 m = -0.09 J.
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Q10. What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 6 Ω in series?
Solution:
R_eq = R1 + R2 + R3 = 2 Ω + 3 Ω + 6 Ω = 11 Ω.
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