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Q1. What is the equivalent capacitance of two capacitors (3 µF and 6 µF) in series?
Solution:
1/Ceq = 1/C1 + 1/C2 = 1/3 + 1/6 = 1/2. Therefore, Ceq = 2 µF.
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Q2. What is the potential difference across a capacitor of 10 µF charged to 5V?
Solution:
The potential difference across a capacitor is equal to the voltage it is charged to, which is 5 V.
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Q3. If a resistor of 10Ω is connected across a 20V power supply, what is the power dissipated by the resistor?
Solution:
Power P = V²/R = (20V)² / 10Ω = 400/10 = 40 W.
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Q4. In a parallel circuit with a 12V battery and two resistors (4Ω and 12Ω), what is the total current supplied by the battery?
Solution:
Total current I = V/R_total. R_total = 1/(1/4 + 1/12) = 3Ω. I = 12V / 3Ω = 4 A.
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Q5. What is the electric potential at a point 3 m away from a charge of +2 µC?
Solution:
V = k * q / r = (8.99 x 10^9 N m²/C²) * (2 x 10^-6 C) / 3 m = 5.99 V.
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Q6. In a series circuit with a 12V battery and two resistors (4Ω and 6Ω), what is the total current flowing through the circuit?
Solution:
Total resistance R = R1 + R2 = 4Ω + 6Ω = 10Ω. Current I = V/R = 12V / 10Ω = 1.2 A.
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