Basic Geometric Concepts - Coordinate Geometry Applications

⏱ Time: 0s

Q1. What is the slope of the line passing through the points (1, 2) and (4, 6)?

Solution:

Slope formula: m = (y2 - y1) / (x2 - x1) = (6 - 2) / (4 - 1) = 4 / 3.

⏱ Time: 0s

Q2. What is the equation of the line that passes through the point (2, 3) with a slope of 2?

Solution:

Using point-slope form: y - y1 = m(x - x1) => y - 3 = 2(x - 2) => y = 2x - 4 + 3 => y = 2x - 1.

⏱ Time: 0s

Q3. What is the equation of the line that passes through the points (1, 2) and (3, 4)?

Solution:

Slope = (4 - 2) / (3 - 1) = 1. Using point-slope form: y - 2 = 1(x - 1) => y = x + 1.

⏱ Time: 0s

Q4. What is the area of a rectangle with vertices at (1, 1), (1, 4), (5, 1), and (5, 4)?

Solution:

Length = 5 - 1 = 4, Width = 4 - 1 = 3. Area = length * width = 4 * 3 = 12.

⏱ Time: 0s

Q5. What is the equation of the line that is perpendicular to y = 2x + 1 and passes through the point (1, 2)?

Solution:

The slope of the perpendicular line is -1/2. Using point-slope form: y - 2 = -1/2(x - 1) => y = -1/2x + 5/2.

⏱ Time: 0s

Q6. If a line has a slope of -3 and passes through the point (2, 5), what is its equation in slope-intercept form?

Solution:

Using y = mx + b: 5 = -3(2) + b => 5 = -6 + b => b = 11. Thus, y = -3x + 11.

⏱ Time: 0s

Q7. If a circle has a radius of 5, what is its area?

Solution:

Area of a circle: A = πr² = π(5)² = 25π.

⏱ Time: 0s

Q8. What is the circumference of a circle with a radius of 5?

Solution:

Circumference = 2πr = 2π(5) = 10π.

⏱ Time: 0s

Q9. What is the length of the diagonal of a rectangle with length 6 and width 8?

Solution:

Using the Pythagorean theorem: d = √(length² + width²) = √(6² + 8²) = √(36 + 64) = √100 = 10.

⏱ Time: 0s

Q10. What is the midpoint of the line segment connecting the points (2, 3) and (8, 7)?

Solution:

Midpoint formula: M = ((x1 + x2)/2, (y1 + y2)/2) = ((2 + 8)/2, (3 + 7)/2) = (5, 5).