Circuit Theory

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Q1. In an AC circuit, what is the phase difference between voltage and current in a purely resistive load?

Solution:

In a purely resistive load, the voltage and current are in phase, meaning the phase difference is 0 degrees.

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Q2. If a circuit has a Norton equivalent current of 2A and a Norton equivalent resistance of 4Ω, what is the Thevenin equivalent voltage?

Solution:

Vth = In * Rn = 2A * 4Ω = 8V.

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Q3. What is the power factor in an AC circuit with a resistive load?

Solution:

The power factor in an AC circuit with a purely resistive load is 1, indicating that all the power is being used effectively.

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Q4. In an AC circuit, what does the term 'impedance' refer to?

Solution:

Impedance is the total opposition that a circuit offers to the flow of alternating current, which includes both resistance and reactance.

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Q5. If a circuit has a Norton equivalent current of 2A and a Norton equivalent resistance of 5Ω, what is the equivalent voltage?

Solution:

V = I * R = 2A * 5Ω = 10V.

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Q6. In a parallel circuit with a 12V source and two resistors of 6Ω and 12Ω, what is the total current drawn from the source?

Solution:

Total current I = V/R_total. R_total = 1/(1/6 + 1/12) = 4Ω. Thus, I = 12V / 4Ω = 3 A.

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Q7. In a circuit with a 12V source and two resistors (3Ω and 6Ω) in parallel, what is the Norton equivalent current (In) at the terminals?

Solution:

Using the formula In = V / R_eq, where R_eq = (3Ω * 6Ω) / (3Ω + 6Ω) = 2Ω, In = 12V / 2Ω = 6A.

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Q8. Using KCL, if three currents entering a node are 5A, 3A, and 2A, what is the total current leaving the node?

Solution:

According to KCL, total current entering = total current leaving. 5A + 3A + 2A = 10A leaving.

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Q9. What is the Norton equivalent current in a circuit?

Solution:

The Norton equivalent current is defined as the current that flows through a short circuit placed across the terminals of the circuit.

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Q10. What is the equivalent resistance of a 5 ohm and a 10 ohm resistor in series?

Solution:

In series, the total resistance is the sum of the individual resistances: R_total = R1 + R2 = 5 ohms + 10 ohms = 15 ohms.