Question: What is the enthalpy change for the reaction: H2(g) + 1/2 O2(g) → H2O(l) at standard conditions?
Options:
-285.8 kJ/mol
0 kJ/mol
285.8 kJ/mol
-241.8 kJ/mol
Correct Answer: -285.8 kJ/mol
Solution:
The standard enthalpy change of formation for water (H2O) is -285.8 kJ/mol.
What is the enthalpy change for the reaction: H2(g) + 1/2 O2(g) → H2O(l) at stan
Practice Questions
Q1
What is the enthalpy change for the reaction: H2(g) + 1/2 O2(g) → H2O(l) at standard conditions?
-285.8 kJ/mol
0 kJ/mol
285.8 kJ/mol
-241.8 kJ/mol
Questions & Step-by-Step Solutions
What is the enthalpy change for the reaction: H2(g) + 1/2 O2(g) → H2O(l) at standard conditions?
Step 1: Understand that the reaction is forming water (H2O) from hydrogen gas (H2) and oxygen gas (O2).
Step 2: Recognize that the enthalpy change for a reaction is the heat energy change that occurs during the reaction.
Step 3: Identify that the standard enthalpy change of formation is a specific value that tells us how much energy is released or absorbed when one mole of a compound is formed from its elements under standard conditions.
Step 4: Look up the standard enthalpy change of formation for water (H2O), which is known to be -285.8 kJ/mol.
Step 5: Conclude that the enthalpy change for the reaction H2(g) + 1/2 O2(g) → H2O(l) is -285.8 kJ/mol, indicating that energy is released when water is formed.
No concepts available.
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