Question: What is the integrated rate law for a second-order reaction?

Options:

1. [A] = [A]0 - kt
2. 1/[A] = 1/[A]0 + kt
3. [A] = [A]0e^(-kt)
4. ln[A] = ln[A]0 - kt

Correct Answer: 1/[A] = 1/[A]0 + kt

Solution:

The integrated rate law for a second-order reaction is given by 1/[A] = 1/[A]0 + kt, where [A]0 is the initial concentration.