If the half-life of a first-order reaction is 10 minutes, what is the rate const

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Question: If the half-life of a first-order reaction is 10 minutes, what is the rate constant?

Options:

Correct Answer: 0.0692 min^-1

Solution:

For a first-order reaction, the half-life (t1/2) is given by t1/2 = 0.693/k. Rearranging gives k = 0.693/t1/2 = 0.693/10 min = 0.0692 min^-1.

If the half-life of a first-order reaction is 10 minutes, what is the rate constant?

If the half-life of a first-order reaction is 10 minutes, what is the rate constant?

Step 1: Understand that we are dealing with a first-order reaction, which has a specific formula for half-life.
Step 2: The formula for the half-life (t1/2) of a first-order reaction is t1/2 = 0.693/k, where k is the rate constant.
Step 3: We know the half-life (t1/2) is given as 10 minutes.
Step 4: Rearrange the formula to solve for k: k = 0.693/t1/2.
Step 5: Substitute the value of t1/2 into the equation: k = 0.693/10 minutes.
Step 6: Calculate the value: k = 0.0693 min^-1.
Step 7: Round the answer to three significant figures if needed: k = 0.0692 min^-1.

First-Order Reaction Kinetics – Understanding the relationship between half-life and rate constant for first-order reactions.
Half-Life Calculation – Using the formula for half-life to derive the rate constant.