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In a first-order reaction, if the half-life is 10 minutes, what is the rate cons

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Question: In a first-order reaction, if the half-life is 10 minutes, what is the rate constant?

Options:

  1. 0.0693 min^-1
  2. 0.1 min^-1
  3. 0.693 min^-1
  4. 0.5 min^-1

Correct Answer: 0.0693 min^-1

Solution: 

For a first-order reaction, the half-life (t1/2) is given by t1/2 = 0.693/k. Rearranging gives k = 0.693/t1/2 = 0.693/10 min = 0.0693 min^-1.

In a first-order reaction, if the half-life is 10 minutes, what is the rate cons

Practice Questions

Q1
In a first-order reaction, if the half-life is 10 minutes, what is the rate constant?
  1. 0.0693 min^-1
  2. 0.1 min^-1
  3. 0.693 min^-1
  4. 0.5 min^-1

Questions & Step-by-Step Solutions

In a first-order reaction, if the half-life is 10 minutes, what is the rate constant?
  • Step 1: Understand that we are dealing with a first-order reaction.
  • Step 2: Know that the formula for the half-life (t1/2) of a first-order reaction is t1/2 = 0.693/k, where k is the rate constant.
  • Step 3: We are given that the half-life (t1/2) is 10 minutes.
  • Step 4: Rearrange the formula to solve for k: k = 0.693/t1/2.
  • Step 5: Substitute the value of t1/2 into the equation: k = 0.693/10 minutes.
  • Step 6: Calculate the value: k = 0.0693 min^-1.
  • First-order reaction kinetics – Understanding the relationship between half-life and rate constant for first-order reactions.
  • Half-life formula – Application of the formula t1/2 = 0.693/k to calculate the rate constant.
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