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What is the rate law for a reaction that is second order in A and first order in

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Question: What is the rate law for a reaction that is second order in A and first order in B?

Options:

  1. Rate = k[A]^2[B]
  2. Rate = k[A][B]^2
  3. Rate = k[A][B]
  4. Rate = k[A]^2 + k[B]

Correct Answer: Rate = k[A]^2[B]

Solution: 

The rate law is determined by the stoichiometry of the rate-determining step. For second order in A and first order in B, the rate law is Rate = k[A]^2[B].

What is the rate law for a reaction that is second order in A and first order in

Practice Questions

Q1
What is the rate law for a reaction that is second order in A and first order in B?
  1. Rate = k[A]^2[B]
  2. Rate = k[A][B]^2
  3. Rate = k[A][B]
  4. Rate = k[A]^2 + k[B]

Questions & Step-by-Step Solutions

What is the rate law for a reaction that is second order in A and first order in B?
  • Step 1: Understand what 'second order in A' means. This means that the concentration of A is squared in the rate law.
  • Step 2: Understand what 'first order in B' means. This means that the concentration of B is to the first power in the rate law.
  • Step 3: Combine the orders of A and B to write the rate law. Since A is second order, we write [A]^2, and since B is first order, we write [B].
  • Step 4: Include the rate constant 'k' in the rate law. The final form will be Rate = k[A]^2[B].
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