If the equilibrium constant Kp for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) is 25
Practice Questions
Q1
If the equilibrium constant Kp for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) is 25 at a certain temperature, what is Kp if the volume of the system is halved?
12.5
25
50
100
Questions & Step-by-Step Solutions
If the equilibrium constant Kp for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) is 25 at a certain temperature, what is Kp if the volume of the system is halved?
Step 1: Understand what Kp is. Kp is the equilibrium constant for a reaction involving gases, and it depends on the concentrations of the gases at equilibrium.
Step 2: Recognize that Kp is defined at a specific temperature and does not change with volume changes. It only changes with temperature.
Step 3: Note that halving the volume of the system will increase the concentrations of the gases, but it will not affect the value of Kp.
Step 4: Conclude that since Kp is independent of volume changes, the value of Kp remains the same at 25.
Equilibrium Constant (Kp) – Kp is a measure of the ratio of the concentrations of products to reactants at equilibrium for a gas-phase reaction, and it is dependent on temperature but not on volume changes.
Le Chatelier's Principle – This principle states that if a system at equilibrium is subjected to a change in conditions, the system will adjust to counteract that change, but Kp itself remains constant unless temperature changes.
