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If the equilibrium constant Kp for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) is 25

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Question: If the equilibrium constant Kp for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) is 25 at a certain temperature, what is Kp if the volume of the system is halved?

Options:

  1. 12.5
  2. 25
  3. 50
  4. 100

Correct Answer: 50

Solution: 

Kp is independent of volume changes; it remains 25.

If the equilibrium constant Kp for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) is 25

Practice Questions

Q1
If the equilibrium constant Kp for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) is 25 at a certain temperature, what is Kp if the volume of the system is halved?
  1. 12.5
  2. 25
  3. 50
  4. 100

Questions & Step-by-Step Solutions

If the equilibrium constant Kp for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) is 25 at a certain temperature, what is Kp if the volume of the system is halved?
  • Step 1: Understand what Kp is. Kp is the equilibrium constant for a reaction involving gases, and it depends on the concentrations of the gases at equilibrium.
  • Step 2: Recognize that Kp is defined at a specific temperature and does not change with volume changes. It only changes with temperature.
  • Step 3: Note that halving the volume of the system will increase the concentrations of the gases, but it will not affect the value of Kp.
  • Step 4: Conclude that since Kp is independent of volume changes, the value of Kp remains the same at 25.
  • Equilibrium Constant (Kp) – Kp is a measure of the ratio of the concentrations of products to reactants at equilibrium for a gas-phase reaction, and it is dependent on temperature but not on volume changes.
  • Le Chatelier's Principle – This principle states that if a system at equilibrium is subjected to a change in conditions, the system will adjust to counteract that change, but Kp itself remains constant unless temperature changes.
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