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In a seesaw, if one child exerts a force of 30 N at a distance of 2 m from the p

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Question: In a seesaw, if one child exerts a force of 30 N at a distance of 2 m from the pivot, what is the torque exerted by that child?

Options:

  1. 15 Nm
  2. 30 Nm
  3. 60 Nm
  4. 0 Nm

Correct Answer: 60 Nm

Solution: 

Torque (τ) = F × r = 30 N × 2 m = 60 Nm.

In a seesaw, if one child exerts a force of 30 N at a distance of 2 m from the p

Practice Questions

Q1
In a seesaw, if one child exerts a force of 30 N at a distance of 2 m from the pivot, what is the torque exerted by that child?
  1. 15 Nm
  2. 30 Nm
  3. 60 Nm
  4. 0 Nm

Questions & Step-by-Step Solutions

In a seesaw, if one child exerts a force of 30 N at a distance of 2 m from the pivot, what is the torque exerted by that child?
  • Step 1: Identify the force exerted by the child, which is 30 N.
  • Step 2: Identify the distance from the pivot to where the force is applied, which is 2 m.
  • Step 3: Use the formula for torque, which is Torque (Ï„) = Force (F) × Distance (r).
  • Step 4: Substitute the values into the formula: Ï„ = 30 N × 2 m.
  • Step 5: Calculate the result: Ï„ = 60 Nm.
  • Torque – Torque is the rotational equivalent of linear force, calculated as the product of the force applied and the distance from the pivot point.
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