A force of 50 N is applied at an angle of 60 degrees to the lever arm of length

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Question: A force of 50 N is applied at an angle of 60 degrees to the lever arm of length 1 m. What is the torque about the pivot?

Options:

Correct Answer: 43.3 Nm

Solution:

Torque (τ) = F × r × sin(θ) = 50 N × 1 m × sin(60°) = 50 N × 1 m × (√3/2) ≈ 43.3 Nm.

A force of 50 N is applied at an angle of 60 degrees to the lever arm of length 1 m. What is the torque about the pivot?

A force of 50 N is applied at an angle of 60 degrees to the lever arm of length 1 m. What is the torque about the pivot?

Step 1: Identify the force applied, which is 50 N.
Step 2: Identify the length of the lever arm, which is 1 m.
Step 3: Identify the angle at which the force is applied, which is 60 degrees.
Step 4: Use the formula for torque: Torque (τ) = Force (F) × Distance (r) × sin(θ).
Step 5: Substitute the values into the formula: τ = 50 N × 1 m × sin(60°).
Step 6: Calculate sin(60°), which is √3/2.
Step 7: Substitute sin(60°) into the equation: τ = 50 N × 1 m × (√3/2).
Step 8: Calculate the torque: τ ≈ 50 N × 1 m × 0.866 (which is √3/2) ≈ 43.3 Nm.

Torque Calculation – Understanding how to calculate torque using the formula τ = F × r × sin(θ), where F is the force applied, r is the distance from the pivot, and θ is the angle between the force and the lever arm.
Trigonometric Functions – Applying the sine function to find the effective component of the force that contributes to torque.