Question: If a rolling object has a mass m and radius r, what is the expression for its total kinetic energy?
Options:
Correct Answer: (1/2)mv^2 + (1/2)(2/5)mr^2(ω^2)
Solution:
The total kinetic energy of a rolling object is the sum of translational and rotational kinetic energy, which can be expressed as (1/2)mv^2 + (1/2)(2/5)mr^2(ω^2).