A spring stretches 5 cm when a load of 10 N is applied. What is the spring const

Practice Questions

Q1
A spring stretches 5 cm when a load of 10 N is applied. What is the spring constant?
  1. 200 N/m
  2. 100 N/m
  3. 50 N/m
  4. 25 N/m

Questions & Step-by-Step Solutions

A spring stretches 5 cm when a load of 10 N is applied. What is the spring constant?
  • Step 1: Understand that Hooke's law states that the force (F) applied to a spring is directly proportional to the extension (x) of the spring. The formula is F = k * x, where k is the spring constant.
  • Step 2: Identify the values given in the problem. The force (F) is 10 N and the extension (x) is 5 cm.
  • Step 3: Convert the extension from centimeters to meters because the standard unit for length in physics is meters. 5 cm is equal to 0.05 m.
  • Step 4: Rearrange Hooke's law to find the spring constant (k). The formula becomes k = F / x.
  • Step 5: Substitute the values into the formula. k = 10 N / 0.05 m.
  • Step 6: Calculate the value of k. 10 N divided by 0.05 m equals 200 N/m.
  • Step 7: Conclude that the spring constant is 200 N/m.
  • Hooke's Law – Hooke's Law states that the force exerted by a spring is directly proportional to the distance it is stretched or compressed, represented by the formula F = kx, where k is the spring constant.
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