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What is the fundamental frequency of a pipe open at both ends that is 2 meters l
Practice Questions
Q1
What is the fundamental frequency of a pipe open at both ends that is 2 meters long?
85 Hz
170 Hz
340 Hz
425 Hz
Questions & Step-by-Step Solutions
What is the fundamental frequency of a pipe open at both ends that is 2 meters long?
Steps
Concepts
Step 1: Understand that we need to find the fundamental frequency of a pipe that is open at both ends.
Step 2: Know that the formula for frequency (f) is f = v/λ, where v is the speed of sound and λ is the wavelength.
Step 3: For a pipe open at both ends, the wavelength (λ) is equal to 2 times the length of the pipe (L). So, λ = 2L.
Step 4: Since the length of the pipe (L) is 2 meters, we calculate λ: λ = 2 * 2 = 4 meters.
Step 5: The speed of sound in air (v) is approximately 343 meters per second.
Step 6: Now, substitute the values into the frequency formula: f = v/λ = 343 / 4.
Step 7: Calculate the frequency: f = 343 / 4 = 85.75 Hz.
No concepts available.
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