What is the bond order of the molecule O2?

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Question: What is the bond order of the molecule O2?

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Correct Answer: 2

Solution:

O2 has 12 total valence electrons. The bond order is calculated as (number of bonding electrons - number of antibonding electrons) / 2 = (10 - 2) / 2 = 4 / 2 = 2.

What is the bond order of the molecule O2?

Practice Questions

What is the bond order of the molecule O2?

Questions & Step-by-Step Solutions

What is the bond order of the molecule O2?

Step 1: Determine the total number of valence electrons for O2. Each oxygen atom has 6 valence electrons, and there are 2 oxygen atoms, so 6 + 6 = 12 valence electrons.
Step 2: Draw the molecular orbital diagram for O2. Place the 12 valence electrons in the appropriate molecular orbitals.
Step 3: Identify the number of bonding electrons. In O2, there are 10 bonding electrons in the bonding orbitals.
Step 4: Identify the number of antibonding electrons. In O2, there are 2 antibonding electrons in the antibonding orbitals.
Step 5: Use the bond order formula: (number of bonding electrons - number of antibonding electrons) / 2.
Step 6: Plug in the numbers: (10 - 2) / 2 = 8 / 2 = 4.
Step 7: The bond order of O2 is 2.

Bond Order Calculation – Bond order is a measure of the number of chemical bonds between a pair of atoms, calculated using the formula (number of bonding electrons - number of antibonding electrons) / 2.
Valence Electrons – Understanding the total number of valence electrons in a molecule is crucial for determining its bond order.
Molecular Orbital Theory – The concept of bonding and antibonding orbitals is essential for calculating bond order in diatomic molecules.

What is the bond order of the molecule O2?

What’s inside this PDF?

What is the bond order of the molecule O2?

Practice Questions

Questions & Step-by-Step Solutions

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