Question: If a metal has a work function of 2 eV, what is the minimum wavelength of light required to cause the photoelectric effect?
Options:
Correct Answer: 310 nm
Solution:
Using the equation λ = hc/E, where E = 2 eV = 2 * 1.6 x 10^-19 J, we find the minimum wavelength λ = (6.63 x 10^-34 J·s * 3 x 10^8 m/s) / (2 * 1.6 x 10^-19 J) = 310 nm.