A 50 kg object is at rest on a surface. What is the normal force acting on it?

Practice Questions

Q1
A 50 kg object is at rest on a surface. What is the normal force acting on it?
  1. 0 N
  2. 50 N
  3. 100 N
  4. 500 N

Questions & Step-by-Step Solutions

A 50 kg object is at rest on a surface. What is the normal force acting on it?
  • Step 1: Identify the mass of the object. In this case, the mass is 50 kg.
  • Step 2: Understand that the normal force is the force that supports the weight of the object resting on a surface.
  • Step 3: Recall the formula for weight, which is F = mg, where F is the weight, m is the mass, and g is the acceleration due to gravity.
  • Step 4: Use the value of g, which is approximately 9.8 m/s².
  • Step 5: Calculate the weight of the object by multiplying the mass (50 kg) by the acceleration due to gravity (9.8 m/s²).
  • Step 6: Perform the calculation: 50 kg * 9.8 m/s² = 490 N.
  • Step 7: Conclude that the normal force acting on the object is 490 N.
  • Normal Force – The normal force is the force exerted by a surface to support the weight of an object resting on it, acting perpendicular to the surface.
  • Weight Calculation – Weight is calculated using the formula F = mg, where m is mass and g is the acceleration due to gravity.
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