Question: What is the orbital speed of a satellite in a circular orbit at a height h above the Earth\'s surface?
Options:
Correct Answer: sqrt(GM/(R+h)^2)
Solution:
The orbital speed v of a satellite in a circular orbit is given by v = sqrt(GM/(R+h)^2), where G is the gravitational constant, M is the mass of the Earth, R is the radius of the Earth, and h is the height of the satellite above the Earth\'s surface.