If a charge of +3μC is placed in an electric field of 500 N/C, what is the force

If a charge of +3μC is placed in an electric field of 500 N/C, what is the force acting on it?

If a charge of +3μC is placed in an electric field of 500 N/C, what is the force acting on it?

Step 1: Identify the charge (q) given in the problem. It is +3μC (microcoulombs).
Step 2: Convert the charge from microcoulombs to coulombs. 1μC = 10^-6 C, so +3μC = 3 × 10^-6 C.
Step 3: Identify the electric field strength (E) given in the problem. It is 500 N/C (newtons per coulomb).
Step 4: Use the formula for force (F) in an electric field, which is F = q * E.
Step 5: Substitute the values into the formula: F = (3 × 10^-6 C) * (500 N/C).
Step 6: Calculate the force: F = 3 × 500 × 10^-6 N = 1500 × 10^-6 N = 0.0015 N.
Step 7: The final answer for the force acting on the charge is 0.0015 N or 1500 μN.

Coulomb's Law – The relationship between electric charge, electric field, and force, expressed as F = q * E.
Units of Measurement – Understanding the units involved, such as microcoulombs (μC) and newtons per coulomb (N/C).