Question: What is the potential difference between two points A and B in an electric field if the work done in moving a charge of 5μC from A to B is 10mJ?
Options:
Correct Answer: 5V
Solution:
Potential difference V = W/Q = 10mJ / 5μC = 10 × 10^-3 J / 5 × 10^-6 C = 2V.