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What is the bond order of the O2 molecule?

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Question: What is the bond order of the O2 molecule?

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Correct Answer: 2

Solution: 

O2 has 12 total electrons, with 10 in bonding orbitals and 2 in antibonding orbitals. Bond order = (number of bonding electrons - number of antibonding electrons) / 2 = (10 - 2) / 2 = 4 / 2 = 2.

What is the bond order of the O2 molecule?

Practice Questions

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What is the bond order of the O2 molecule?
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Questions & Step-by-Step Solutions

What is the bond order of the O2 molecule?
  • Step 1: Determine the total number of electrons in the O2 molecule. Oxygen has 8 electrons, so O2 has 8 + 8 = 16 electrons.
  • Step 2: Identify how many of these electrons are in bonding orbitals and how many are in antibonding orbitals. For O2, there are 10 electrons in bonding orbitals and 6 electrons in antibonding orbitals.
  • Step 3: Calculate the bond order using the formula: Bond Order = (number of bonding electrons - number of antibonding electrons) / 2.
  • Step 4: Substitute the values into the formula: Bond Order = (10 - 6) / 2.
  • Step 5: Simplify the equation: Bond Order = 4 / 2 = 2.
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