If the resistance R2 in a Wheatstone bridge is halved, what effect does it have

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Question: If the resistance R2 in a Wheatstone bridge is halved, what effect does it have on the balance condition?

Options:

Correct Answer: The bridge becomes unbalanced

Solution:

Halving R2 will disturb the balance condition, making the bridge unbalanced.

If the resistance R2 in a Wheatstone bridge is halved, what effect does it have on the balance condition?

If the resistance R2 in a Wheatstone bridge is halved, what effect does it have on the balance condition?

Step 1: Understand what a Wheatstone bridge is. It is a circuit used to measure unknown resistances by balancing two legs of a bridge circuit.
Step 2: Identify the components of the Wheatstone bridge. It has four resistors: R1, R2, R3, and R4, and a voltage source.
Step 3: Know the balance condition. The bridge is balanced when the ratio of the resistances in one leg equals the ratio in the other leg: (R1/R2) = (R3/R4).
Step 4: Consider what happens when R2 is halved. If R2 becomes R2/2, the ratio (R1/R2) changes because R2 is now smaller.
Step 5: Analyze the new balance condition. The new ratio becomes (R1/(R2/2)) = (2*R1/R2). This means the left side of the equation increases.
Step 6: Conclude that since the left side of the balance condition increases, it will no longer equal the right side (R3/R4), making the bridge unbalanced.

Wheatstone Bridge Balance Condition – The balance condition of a Wheatstone bridge is determined by the ratio of the resistances in the two branches. If one resistance is changed, it can disturb the balance.