If two resistors of resistivity 5 Ω·m and 10 Ω·m are connected in series, what i

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Question: If two resistors of resistivity 5 Ω·m and 10 Ω·m are connected in series, what is the total resistance?

Options:

Correct Answer: 15 Ω

Solution:

Total resistance in series is the sum: R_total = R1 + R2 = 5 + 10 = 15 Ω.

If two resistors of resistivity 5 Ω·m and 10 Ω·m are connected in series, what is the total resistance?

If two resistors of resistivity 5 Ω·m and 10 Ω·m are connected in series, what is the total resistance?

Step 1: Identify the resistances of the two resistors. The first resistor has a resistance of 5 Ω and the second resistor has a resistance of 10 Ω.
Step 2: Understand that when resistors are connected in series, the total resistance is found by adding the individual resistances together.
Step 3: Write the formula for total resistance in series: R_total = R1 + R2.
Step 4: Substitute the values of the resistances into the formula: R_total = 5 Ω + 10 Ω.
Step 5: Perform the addition: 5 + 10 = 15.
Step 6: Conclude that the total resistance of the two resistors in series is 15 Ω.

Series Resistance Calculation – In a series circuit, the total resistance is the sum of the individual resistances.