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In a series circuit with a 12V battery and two resistors of 3Ω and 6Ω, what is t

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Question: In a series circuit with a 12V battery and two resistors of 3Ω and 6Ω, what is the current flowing through the circuit?

Options:

  1. 1A
  2. 2A
  3. 3A
  4. 4A

Correct Answer: 2A

Solution: 

Total resistance R = R1 + R2 = 3Ω + 6Ω = 9Ω. Current I = V/R = 12V/9Ω = 4/3A.

In a series circuit with a 12V battery and two resistors of 3Ω and 6Ω, what is t

Practice Questions

Q1
In a series circuit with a 12V battery and two resistors of 3Ω and 6Ω, what is the current flowing through the circuit?
  1. 1A
  2. 2A
  3. 3A
  4. 4A

Questions & Step-by-Step Solutions

In a series circuit with a 12V battery and two resistors of 3Ω and 6Ω, what is the current flowing through the circuit?
  • Step 1: Identify the voltage of the battery, which is 12V.
  • Step 2: Identify the resistors in the circuit, which are 3Ω and 6Ω.
  • Step 3: Calculate the total resistance in the circuit by adding the resistances together: 3Ω + 6Ω = 9Ω.
  • Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
  • Step 5: Substitute the values into the formula: I = 12V / 9Ω.
  • Step 6: Simplify the calculation: 12V / 9Ω = 4/3A.
  • Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
  • Series Circuit – A circuit configuration where components are connected end-to-end, resulting in the same current flowing through each component.
  • Total Resistance in Series – In a series circuit, the total resistance is the sum of the individual resistances.
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