A box contains 5 red, 3 green, and 2 blue marbles. What is the probability of dr
Practice Questions
Q1
A box contains 5 red, 3 green, and 2 blue marbles. What is the probability of drawing a green marble given that the marble drawn is not blue?
3/10
1/3
1/5
1/2
Questions & Step-by-Step Solutions
A box contains 5 red, 3 green, and 2 blue marbles. What is the probability of drawing a green marble given that the marble drawn is not blue?
Step 1: Count the total number of marbles in the box. There are 5 red, 3 green, and 2 blue marbles.
Step 2: Calculate the total number of marbles: 5 (red) + 3 (green) + 2 (blue) = 10 marbles.
Step 3: Identify the marbles that are not blue. Since there are 5 red and 3 green, the total number of non-blue marbles is 5 + 3 = 8.
Step 4: Determine how many of the non-blue marbles are green. There are 3 green marbles.
Step 5: Calculate the probability of drawing a green marble from the non-blue marbles. This is done by dividing the number of green marbles by the total number of non-blue marbles: 3 (green) / 8 (non-blue) = 3/8.
Step 6: Conclude that the probability of drawing a green marble given that the marble drawn is not blue is 3/8.
Conditional Probability – The probability of an event occurring given that another event has already occurred.
Total Outcomes – Understanding the total number of favorable outcomes in relation to the total possible outcomes.
