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A box contains 5 red, 3 green, and 2 blue marbles. What is the probability of dr

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Question: A box contains 5 red, 3 green, and 2 blue marbles. What is the probability of drawing a green marble given that the marble drawn is not blue?

Options:

  1. 3/10
  2. 1/3
  3. 1/5
  4. 1/2

Correct Answer: 3/10

Solution: 

The total number of marbles that are not blue is 8 (5 red + 3 green). The probability of drawing a green marble is 3/8.

A box contains 5 red, 3 green, and 2 blue marbles. What is the probability of dr

Practice Questions

Q1
A box contains 5 red, 3 green, and 2 blue marbles. What is the probability of drawing a green marble given that the marble drawn is not blue?
  1. 3/10
  2. 1/3
  3. 1/5
  4. 1/2

Questions & Step-by-Step Solutions

A box contains 5 red, 3 green, and 2 blue marbles. What is the probability of drawing a green marble given that the marble drawn is not blue?
  • Step 1: Count the total number of marbles in the box. There are 5 red, 3 green, and 2 blue marbles.
  • Step 2: Calculate the total number of marbles: 5 (red) + 3 (green) + 2 (blue) = 10 marbles.
  • Step 3: Identify the marbles that are not blue. Since there are 5 red and 3 green, the total number of non-blue marbles is 5 + 3 = 8.
  • Step 4: Determine how many of the non-blue marbles are green. There are 3 green marbles.
  • Step 5: Calculate the probability of drawing a green marble from the non-blue marbles. This is done by dividing the number of green marbles by the total number of non-blue marbles: 3 (green) / 8 (non-blue) = 3/8.
  • Step 6: Conclude that the probability of drawing a green marble given that the marble drawn is not blue is 3/8.
  • Conditional Probability – The probability of an event occurring given that another event has already occurred.
  • Total Outcomes – Understanding the total number of favorable outcomes in relation to the total possible outcomes.
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