If 5 moles of KCl are dissolved in 3 kg of water, what is the molality of the so

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Question: If 5 moles of KCl are dissolved in 3 kg of water, what is the molality of the solution?

Options:

Correct Answer: 1.67 m

Solution:

Molality (m) = moles of solute / kg of solvent = 5 moles / 3 kg = 1.67 m.

If 5 moles of KCl are dissolved in 3 kg of water, what is the molality of the solution?

If 5 moles of KCl are dissolved in 3 kg of water, what is the molality of the solution?

Step 1: Identify the number of moles of solute (KCl) in the solution. In this case, it is 5 moles.
Step 2: Identify the mass of the solvent (water) in kilograms. Here, it is 3 kg.
Step 3: Use the formula for molality, which is molality (m) = moles of solute / kg of solvent.
Step 4: Plug in the values into the formula: m = 5 moles / 3 kg.
Step 5: Calculate the result: 5 divided by 3 equals approximately 1.67.
Step 6: State the final answer: The molality of the solution is 1.67 m.

Molality – Molality is a measure of the concentration of a solute in a solution, defined as the number of moles of solute per kilogram of solvent.