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A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the

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Question: A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)

Options:

  1. 1 M
  2. 2 M
  3. 0.5 M
  4. 0.1 M

Correct Answer: 1 M

Solution:

Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = moles of solute / liters of solution = 1 mole / 1 L = 1 M.

A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the

Practice Questions

Q1
A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)
  1. 1 M
  2. 2 M
  3. 0.5 M
  4. 0.1 M

Questions & Step-by-Step Solutions

A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)
  • Step 1: Identify the mass of NaCl used, which is 58.5 grams.
  • Step 2: Identify the molar mass of NaCl, which is given as 58.5 g/mol.
  • Step 3: Calculate the number of moles of NaCl by dividing the mass by the molar mass: 58.5 g / 58.5 g/mol = 1 mole.
  • Step 4: Identify the volume of the solution, which is 1 liter.
  • Step 5: Calculate the molarity of the solution using the formula: Molarity = moles of solute / liters of solution.
  • Step 6: Substitute the values into the formula: Molarity = 1 mole / 1 L = 1 M.
  • Molarity – Molarity is a measure of the concentration of a solute in a solution, defined as the number of moles of solute per liter of solution.
  • Moles Calculation – Calculating moles involves dividing the mass of the solute by its molar mass.
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