What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2

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Question: What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))

Options:

Correct Answer: 6.13 atm

Solution:

Osmotic pressure (π) = nRT/V = (0.5 moles)(0.0821 L·atm/(K·mol))(298 K) / 2 L = 6.13 atm.

What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))

What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))

Step 1: Identify the formula for osmotic pressure, which is π = nRT/V.
Step 2: Determine the values needed for the formula: n (number of moles) = 0.5 moles, R (ideal gas constant) = 0.0821 L·atm/(K·mol), T (temperature in Kelvin) = 25 °C + 273 = 298 K, and V (volume in liters) = 2 L.
Step 3: Plug the values into the osmotic pressure formula: π = (0.5 moles)(0.0821 L·atm/(K·mol))(298 K) / 2 L.
Step 4: Calculate the numerator: (0.5)(0.0821)(298) = 12.2953.
Step 5: Divide the result from Step 4 by the volume (2 L): 12.2953 / 2 = 6.14765.
Step 6: Round the final answer to two decimal places: 6.15 atm.

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