How many moles of oxygen are required to completely react with 4 moles of ethane

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Question: How many moles of oxygen are required to completely react with 4 moles of ethane (C2H6)?

Options:

Correct Answer: 7 moles

Solution:

The balanced equation is 2C2H6 + 7O2 → 4CO2 + 6H2O. Therefore, 4 moles of C2H6 require 14 moles of O2, which means 7 moles of O2 for 2 moles of C2H6.

How many moles of oxygen are required to completely react with 4 moles of ethane (C2H6)?

How many moles of oxygen are required to completely react with 4 moles of ethane (C2H6)?

Step 1: Write down the chemical formula for ethane, which is C2H6.
Step 2: Write the balanced chemical equation for the combustion of ethane: 2C2H6 + 7O2 → 4CO2 + 6H2O.
Step 3: Identify the ratio of ethane (C2H6) to oxygen (O2) in the balanced equation. For every 2 moles of C2H6, 7 moles of O2 are required.
Step 4: Determine how many moles of O2 are needed for 4 moles of C2H6. Since 2 moles of C2H6 require 7 moles of O2, 4 moles of C2H6 will require double that amount.
Step 5: Calculate the moles of O2 needed: 4 moles of C2H6 require (4 moles C2H6 / 2 moles C2H6) * 7 moles O2 = 14 moles O2.

Stoichiometry – Understanding the mole ratio between reactants and products in a balanced chemical equation.
Balancing Chemical Equations – The ability to correctly balance a chemical equation to determine the correct ratios of reactants and products.