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If 10 grams of calcium carbonate (CaCO3) decomposes, how many grams of calcium o

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Question: If 10 grams of calcium carbonate (CaCO3) decomposes, how many grams of calcium oxide (CaO) are produced?

Options:

  1. 5 g
  2. 10 g
  3. 8 g
  4. 7 g

Correct Answer: 8 g

Solution: 

The balanced equation is CaCO3 → CaO + CO2. The molar mass of CaCO3 is 100 g/mol and CaO is 56 g/mol. Thus, 10 g of CaCO3 produces (10 g / 100 g/mol) x 56 g/mol = 5.6 g of CaO.

If 10 grams of calcium carbonate (CaCO3) decomposes, how many grams of calcium o

Practice Questions

Q1
If 10 grams of calcium carbonate (CaCO3) decomposes, how many grams of calcium oxide (CaO) are produced?
  1. 5 g
  2. 10 g
  3. 8 g
  4. 7 g

Questions & Step-by-Step Solutions

If 10 grams of calcium carbonate (CaCO3) decomposes, how many grams of calcium oxide (CaO) are produced?
  • Step 1: Write down the chemical equation for the decomposition of calcium carbonate: CaCO3 → CaO + CO2.
  • Step 2: Calculate the molar mass of calcium carbonate (CaCO3). It is 40 (Ca) + 12 (C) + 48 (O3) = 100 grams per mole.
  • Step 3: Calculate the molar mass of calcium oxide (CaO). It is 40 (Ca) + 16 (O) = 56 grams per mole.
  • Step 4: Determine how many moles of CaCO3 are in 10 grams. Use the formula: moles = mass / molar mass. So, moles of CaCO3 = 10 g / 100 g/mol = 0.1 moles.
  • Step 5: Use the balanced equation to find out how many moles of CaO are produced. From the equation, 1 mole of CaCO3 produces 1 mole of CaO, so 0.1 moles of CaCO3 will produce 0.1 moles of CaO.
  • Step 6: Convert the moles of CaO back to grams. Use the formula: mass = moles x molar mass. So, mass of CaO = 0.1 moles x 56 g/mol = 5.6 grams.
  • Stoichiometry – The calculation of reactants and products in chemical reactions based on balanced equations.
  • Molar Mass Calculation – Determining the mass of a substance based on its molar mass to convert between grams and moles.
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