What is the product of the elimination reaction of 2-bromobutane with KOH in eth
Practice Questions
Q1
What is the product of the elimination reaction of 2-bromobutane with KOH in ethanol?
But-1-ene
But-2-ene
But-3-ene
Butane
Questions & Step-by-Step Solutions
What is the product of the elimination reaction of 2-bromobutane with KOH in ethanol?
Step 1: Identify the starting material, which is 2-bromobutane. This compound has a bromine atom attached to the second carbon of a four-carbon chain.
Step 2: Recognize that KOH (potassium hydroxide) is a strong base that can facilitate an elimination reaction.
Step 3: Understand that in an elimination reaction, the bromine atom will be removed along with a hydrogen atom from an adjacent carbon, forming a double bond.
Step 4: Determine the possible products. In this case, the elimination can occur in two ways: removing a hydrogen from the first carbon or the third carbon.
Step 5: Calculate the products: Removing a hydrogen from the first carbon leads to but-1-ene, while removing from the third carbon leads to but-2-ene.
Step 6: Compare the stability of the products. But-2-ene is more stable than but-1-ene because it is a more substituted alkene.
Step 7: Conclude that the major product of the elimination reaction of 2-bromobutane with KOH in ethanol is but-2-ene.
