Which of the following compounds undergoes elimination to form an alkene most re

₹0.0

Question: Which of the following compounds undergoes elimination to form an alkene most readily?

Options:

Correct Answer: 3-bromopropane

Solution:

3-bromopropane undergoes elimination more readily due to the stability of the tertiary carbocation formed during the reaction.

Which of the following compounds undergoes elimination to form an alkene most readily?

Which of the following compounds undergoes elimination to form an alkene most readily?

Step 1: Understand what elimination means. Elimination is a chemical reaction where atoms or groups are removed from a molecule, often forming a double bond (alkene).
Step 2: Identify the compounds given in the question. We need to compare them to see which one can easily lose atoms/groups.
Step 3: Know about carbocations. A carbocation is a positively charged carbon atom. The stability of this carbocation affects how easily elimination can happen.
Step 4: Recognize that tertiary carbocations (where the carbon is connected to three other carbons) are more stable than secondary or primary carbocations.
Step 5: Determine which compound forms a tertiary carbocation upon elimination. In this case, 3-bromopropane forms a tertiary carbocation.
Step 6: Conclude that since 3-bromopropane forms a stable tertiary carbocation, it undergoes elimination to form an alkene more readily than the others.

No concepts available.