What is the stereochemical configuration of 2-bromo-3-methylpentane at the chira

Practice Questions

Q1
What is the stereochemical configuration of 2-bromo-3-methylpentane at the chiral center?
  1. R
  2. S
  3. E
  4. Z

Questions & Step-by-Step Solutions

What is the stereochemical configuration of 2-bromo-3-methylpentane at the chiral center?
  • Step 1: Identify the chiral center in 2-bromo-3-methylpentane. A chiral center is a carbon atom that is attached to four different groups.
  • Step 2: Look at the carbon atom at position 2, which is attached to a bromine (Br), a methyl group (CH3), an ethyl group (C2H5), and the rest of the pentane chain.
  • Step 3: Assign priorities to the four groups based on atomic number. The group with the highest atomic number gets the highest priority.
  • Step 4: The bromine (Br) has the highest priority (1), followed by the ethyl group (2), the methyl group (3), and the hydrogen (H) which is the lowest priority (4).
  • Step 5: Arrange the groups in order of priority around the chiral center. If you look from the lowest priority group (H) to the highest (Br), determine the direction of the arrangement.
  • Step 6: If the arrangement of the highest priority groups (Br, ethyl, methyl) goes in a clockwise direction, the configuration is R. If it goes counterclockwise, it is S.
  • Step 7: In this case, the arrangement is clockwise, so the stereochemical configuration of 2-bromo-3-methylpentane at the chiral center is R.
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