What is the product of the Friedel-Crafts alkylation of benzene with 1-bromopropane in the presence of AlCl3?

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Q: What is the product of the Friedel-Crafts alkylation of benzene with 1-bromopropane in the presence of AlCl3?

Solution: The product is propylbenzene, formed when benzene reacts with 1-bromopropane in the presence of AlCl3, which generates a propyl cation.

Steps: 8

Step 1: Start with benzene, which is a ring of six carbon atoms with alternating double bonds.
Step 2: Introduce 1-bromopropane, which is a three-carbon chain (propyl group) attached to a bromine atom.
Step 3: Add AlCl3 (aluminum chloride) to the mixture. This compound helps to activate the 1-bromopropane.
Step 4: The AlCl3 interacts with 1-bromopropane, causing the bromine atom to leave and forming a propyl cation (a positively charged three-carbon ion).
Step 5: The propyl cation is now reactive and can attack the benzene ring.
Step 6: The propyl cation bonds with one of the carbon atoms in the benzene ring, breaking one of the double bonds and forming a new single bond.
Step 7: The result is a new compound where the propyl group is attached to the benzene ring, which is called propylbenzene.
Step 8: Finally, the reaction is complete, and the product is propylbenzene.