What is the major product of the reaction of 1-bromo-2-methylpropane with sodium

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Question: What is the major product of the reaction of 1-bromo-2-methylpropane with sodium hydroxide in ethanol?

Options:

Correct Answer: 2-methylpropene

Solution:

The reaction is an elimination reaction (E2) leading to the formation of 2-methylpropene as the major product.

What is the major product of the reaction of 1-bromo-2-methylpropane with sodium hydroxide in ethanol?

What is the major product of the reaction of 1-bromo-2-methylpropane with sodium hydroxide in ethanol?

Step 1: Identify the reactants. We have 1-bromo-2-methylpropane and sodium hydroxide in ethanol.
Step 2: Recognize the type of reaction. Sodium hydroxide (NaOH) can act as a strong base, which suggests that an elimination reaction (E2) may occur.
Step 3: Understand the structure of 1-bromo-2-methylpropane. It has a bromine atom attached to the first carbon and a methyl group on the second carbon.
Step 4: In an E2 reaction, the base (NaOH) removes a hydrogen atom from a carbon adjacent to the carbon with the bromine atom, while the bromine leaves, forming a double bond.
Step 5: Determine which hydrogen will be removed. The hydrogen on the second carbon (where the methyl group is) is removed, leading to the formation of a double bond between the first and second carbons.
Step 6: Draw the product. The double bond between the first and second carbons creates 2-methylpropene as the major product.

No concepts available.