A roller coaster starts from rest at a height of 50 m. What is its speed at the
Practice Questions
Q1
A roller coaster starts from rest at a height of 50 m. What is its speed at the lowest point? (g = 9.8 m/s²)
10 m/s
20 m/s
30 m/s
40 m/s
Questions & Step-by-Step Solutions
A roller coaster starts from rest at a height of 50 m. What is its speed at the lowest point? (g = 9.8 m/s²)
Step 1: Understand that the roller coaster starts from a height of 50 meters and is initially at rest, meaning its initial speed is 0 m/s.
Step 2: Recognize that as the roller coaster descends, potential energy (due to its height) is converted into kinetic energy (due to its speed).
Step 3: Use the formula for potential energy: PE = mgh, where m is mass, g is the acceleration due to gravity (9.8 m/s²), and h is height (50 m).
Step 4: Use the formula for kinetic energy: KE = 0.5mv², where v is the speed we want to find.
Step 5: Set the potential energy equal to the kinetic energy at the lowest point: mgh = 0.5mv².
Step 6: Notice that mass (m) cancels out from both sides of the equation, simplifying it to gh = 0.5v².
Step 7: Rearrange the equation to solve for v: v² = 2gh.
Step 8: Substitute the values for g (9.8 m/s²) and h (50 m) into the equation: v² = 2 * 9.8 * 50.
Step 9: Calculate the right side: v² = 980.
Step 10: Take the square root of both sides to find v: v = sqrt(980).
Step 11: Calculate the square root: v ≈ 31.3 m/s.
Conservation of Energy – The principle that energy cannot be created or destroyed, only transformed from one form to another, in this case from potential energy to kinetic energy.
Kinetic and Potential Energy – Understanding the relationship between potential energy (mgh) at height and kinetic energy (0.5mv²) at the lowest point.
Gravitational Acceleration – The constant acceleration due to gravity (g = 9.8 m/s²) that affects the motion of the roller coaster.