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A voltage is measured as 12.0 V with an uncertainty of ±0.2 V. What is the maxim

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Question: A voltage is measured as 12.0 V with an uncertainty of ±0.2 V. What is the maximum possible voltage?

Options:

  1. 11.8 V
  2. 12.0 V
  3. 12.2 V
  4. 12.4 V

Correct Answer: 12.2 V

Solution: 

Maximum possible voltage = Measured value + Uncertainty = 12.0 + 0.2 = 12.2 V.

A voltage is measured as 12.0 V with an uncertainty of ±0.2 V. What is the maxim

Practice Questions

Q1
A voltage is measured as 12.0 V with an uncertainty of ±0.2 V. What is the maximum possible voltage?
  1. 11.8 V
  2. 12.0 V
  3. 12.2 V
  4. 12.4 V

Questions & Step-by-Step Solutions

A voltage is measured as 12.0 V with an uncertainty of ±0.2 V. What is the maximum possible voltage?
  • Step 1: Identify the measured voltage, which is 12.0 V.
  • Step 2: Identify the uncertainty, which is ±0.2 V.
  • Step 3: To find the maximum possible voltage, add the uncertainty to the measured voltage.
  • Step 4: Perform the calculation: 12.0 V + 0.2 V = 12.2 V.
  • Step 5: The maximum possible voltage is 12.2 V.
  • Measurement and Uncertainty – Understanding how to calculate maximum and minimum values based on a measured value and its associated uncertainty.
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