In a simple harmonic oscillator, if the maximum speed is 4 m/s and the amplitude

Practice Questions

Q1
In a simple harmonic oscillator, if the maximum speed is 4 m/s and the amplitude is 2 m, what is the angular frequency?
  1. 2 rad/s
  2. 4 rad/s
  3. 6 rad/s
  4. 8 rad/s

Questions & Step-by-Step Solutions

In a simple harmonic oscillator, if the maximum speed is 4 m/s and the amplitude is 2 m, what is the angular frequency?
  • Step 1: Identify the maximum speed (v_max) given in the problem, which is 4 m/s.
  • Step 2: Identify the amplitude (A) given in the problem, which is 2 m.
  • Step 3: Recall the formula for maximum speed in a simple harmonic oscillator, which is v_max = ωA, where ω is the angular frequency.
  • Step 4: Rearrange the formula to solve for angular frequency (ω): ω = v_max / A.
  • Step 5: Substitute the values into the formula: ω = 4 m/s / 2 m.
  • Step 6: Calculate the result: ω = 2 rad/s.
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