In double-slit diffraction, what is the path difference for constructive interfe

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Question: In double-slit diffraction, what is the path difference for constructive interference at the first order maximum?

Options:

Correct Answer: λ

Solution:

For constructive interference, the path difference must be an integer multiple of the wavelength, so for the first order maximum, it is λ.

In double-slit diffraction, what is the path difference for constructive interference at the first order maximum?

In double-slit diffraction, what is the path difference for constructive interference at the first order maximum?

Step 1: Understand that in double-slit diffraction, light waves pass through two slits and create interference patterns.
Step 2: Know that constructive interference occurs when the waves from the two slits meet in phase, meaning they add together to make a brighter light.
Step 3: Realize that for constructive interference, the path difference (the difference in distance traveled by the two waves) must be an integer multiple of the wavelength (λ).
Step 4: Identify that the first order maximum refers to the first bright spot in the interference pattern after the central maximum.
Step 5: For the first order maximum, the path difference is equal to one wavelength (λ).

Path Difference in Interference – The difference in distance traveled by two waves arriving at a point, which determines whether they interfere constructively or destructively.
Constructive Interference – Occurs when the path difference between two waves is an integer multiple of the wavelength, leading to an increase in amplitude.
Order of Maximum – Refers to the specific points of constructive interference, with the first order maximum being the first point where this occurs.