What is the primary oxidation state of manganese in potassium permanganate (KMnO

Practice Questions

Q1
What is the primary oxidation state of manganese in potassium permanganate (KMnO4)?
  1. +2
  2. +4
  3. +6
  4. +7

Questions & Step-by-Step Solutions

What is the primary oxidation state of manganese in potassium permanganate (KMnO4)?
  • Step 1: Identify the chemical formula of potassium permanganate, which is KMnO4.
  • Step 2: Recognize that potassium (K) has an oxidation state of +1.
  • Step 3: Understand that oxygen (O) typically has an oxidation state of -2.
  • Step 4: Since there are 4 oxygen atoms in KMnO4, calculate the total oxidation state contributed by oxygen: 4 O x -2 = -8.
  • Step 5: Set up the equation for the overall charge of the compound, which is neutral (0): +1 (from K) + x (from Mn) + (-8) (from O) = 0.
  • Step 6: Solve the equation: +1 + x - 8 = 0, which simplifies to x - 7 = 0, so x = +7.
  • Step 7: Conclude that the oxidation state of manganese (Mn) in potassium permanganate (KMnO4) is +7.
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