What is the primary oxidation state of manganese in potassium permanganate (KMnO

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Question: What is the primary oxidation state of manganese in potassium permanganate (KMnO4)?

Options:

Correct Answer: +7

Solution:

In potassium permanganate, manganese has an oxidation state of +7, which is characteristic of its highest oxidation state.

What is the primary oxidation state of manganese in potassium permanganate (KMnO4)?

What is the primary oxidation state of manganese in potassium permanganate (KMnO4)?

Step 1: Identify the chemical formula of potassium permanganate, which is KMnO4.
Step 2: Recognize that potassium (K) has an oxidation state of +1.
Step 3: Understand that oxygen (O) typically has an oxidation state of -2.
Step 4: Since there are 4 oxygen atoms in KMnO4, calculate the total oxidation state contributed by oxygen: 4 O x -2 = -8.
Step 5: Set up the equation for the overall charge of the compound, which is neutral (0): +1 (from K) + x (from Mn) + (-8) (from O) = 0.
Step 6: Solve the equation: +1 + x - 8 = 0, which simplifies to x - 7 = 0, so x = +7.
Step 7: Conclude that the oxidation state of manganese (Mn) in potassium permanganate (KMnO4) is +7.

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