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In an AC circuit, if the voltage is given by V(t) = V_0 sin(ωt), what is the exp

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Question: In an AC circuit, if the voltage is given by V(t) = V_0 sin(ωt), what is the expression for the current through a resistor R?

Options:

  1. I(t) = (V_0/R) sin(ωt)
  2. I(t) = (V_0/R) cos(ωt)
  3. I(t) = (R/V_0) sin(ωt)
  4. I(t) = (R/V_0) cos(ωt)

Correct Answer: I(t) = (V_0/R) sin(ωt)

Solution:

For a resistor, the current is in phase with the voltage. Therefore, I(t) = V(t)/R = (V_0/R) sin(ωt).

In an AC circuit, if the voltage is given by V(t) = V_0 sin(ωt), what is the exp

Practice Questions

Q1
In an AC circuit, if the voltage is given by V(t) = V_0 sin(ωt), what is the expression for the current through a resistor R?
  1. I(t) = (V_0/R) sin(ωt)
  2. I(t) = (V_0/R) cos(ωt)
  3. I(t) = (R/V_0) sin(ωt)
  4. I(t) = (R/V_0) cos(ωt)

Questions & Step-by-Step Solutions

In an AC circuit, if the voltage is given by V(t) = V_0 sin(ωt), what is the expression for the current through a resistor R?
  • Step 1: Understand that in an AC circuit, voltage can change over time. Here, the voltage is given by the formula V(t) = V_0 sin(ωt).
  • Step 2: Recognize that V_0 is the maximum voltage, ω is the angular frequency, and t is time.
  • Step 3: Know that in a resistor, the current (I) is directly related to the voltage (V) by Ohm's Law, which states I = V/R.
  • Step 4: Substitute the expression for voltage into Ohm's Law. So, I(t) = V(t)/R = (V_0 sin(ωt))/R.
  • Step 5: Simplify the expression. This gives I(t) = (V_0/R) sin(ωt).
  • Step 6: Conclude that the current through the resistor is also a sine wave, just like the voltage, but scaled by the factor of 1/R.
  • Ohm's Law – The relationship between voltage, current, and resistance in a circuit, expressed as V = IR.
  • AC Circuit Behavior – Understanding how alternating current (AC) behaves in relation to voltage and current, particularly in resistive components.
  • Phase Relationship – The concept that current and voltage are in phase for resistors, meaning they reach their maximum and minimum values simultaneously.
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