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A box is pushed with a force of 50 N on a surface with a coefficient of kinetic

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Question: A box is pushed with a force of 50 N on a surface with a coefficient of kinetic friction of 0.3. If the normal force is 100 N, what is the net force acting on the box?

Options:

  1. 20 N
  2. 30 N
  3. 50 N
  4. 70 N

Correct Answer: 30 N

Solution: 

Frictional force = μk * N = 0.3 * 100 N = 30 N. Net force = applied force - frictional force = 50 N - 30 N = 20 N.

A box is pushed with a force of 50 N on a surface with a coefficient of kinetic

Practice Questions

Q1
A box is pushed with a force of 50 N on a surface with a coefficient of kinetic friction of 0.3. If the normal force is 100 N, what is the net force acting on the box?
  1. 20 N
  2. 30 N
  3. 50 N
  4. 70 N

Questions & Step-by-Step Solutions

A box is pushed with a force of 50 N on a surface with a coefficient of kinetic friction of 0.3. If the normal force is 100 N, what is the net force acting on the box?
Correct Answer: 20 N
  • Step 1: Identify the applied force on the box, which is given as 50 N.
  • Step 2: Identify the coefficient of kinetic friction, which is given as 0.3.
  • Step 3: Identify the normal force acting on the box, which is given as 100 N.
  • Step 4: Calculate the frictional force using the formula: Frictional force = μk * N.
  • Step 5: Substitute the values into the formula: Frictional force = 0.3 * 100 N.
  • Step 6: Calculate the frictional force: Frictional force = 30 N.
  • Step 7: Calculate the net force acting on the box using the formula: Net force = applied force - frictional force.
  • Step 8: Substitute the values into the formula: Net force = 50 N - 30 N.
  • Step 9: Calculate the net force: Net force = 20 N.
  • Newton's Second Law – Understanding the relationship between force, mass, and acceleration, particularly how net force is calculated.
  • Friction – Calculating the frictional force using the coefficient of kinetic friction and the normal force.
  • Net Force – Determining the net force by subtracting the frictional force from the applied force.
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