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A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is t

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Question: A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the maximum force exerted by the spring when it is compressed by 0.1 m?

Options:

  1. 2 N
  2. 5 N
  3. 20 N
  4. 10 N

Correct Answer: 20 N

Solution: 

Using Hooke\'s law, F = kx = 200 N/m * 0.1 m = 20 N.

A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is t

Practice Questions

Q1
A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the maximum force exerted by the spring when it is compressed by 0.1 m?
  1. 2 N
  2. 5 N
  3. 20 N
  4. 10 N

Questions & Step-by-Step Solutions

A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the maximum force exerted by the spring when it is compressed by 0.1 m?
  • Step 1: Identify the spring constant (k). In this case, k = 200 N/m.
  • Step 2: Identify the amount the spring is compressed (x). Here, x = 0.1 m.
  • Step 3: Use Hooke's law formula, which is F = k * x.
  • Step 4: Substitute the values into the formula: F = 200 N/m * 0.1 m.
  • Step 5: Calculate the force: F = 20 N.
  • Hooke's Law – The principle that the force exerted by a spring is directly proportional to the distance it is compressed or stretched, represented by the formula F = kx.
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