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A train moving with a speed of 60 km/h applies brakes and comes to a stop in 5 s

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Question: A train moving with a speed of 60 km/h applies brakes and comes to a stop in 5 seconds. What is the magnitude of its acceleration?

Options:

  1. -3 m/s²
  2. -2 m/s²
  3. -1 m/s²
  4. -4 m/s²

Correct Answer: -3 m/s²

Solution: 

First, convert speed to m/s: 60 km/h = 60/3.6 = 16.67 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 16.67) / 5 = -3.33 m/s², approximately -3 m/s².

A train moving with a speed of 60 km/h applies brakes and comes to a stop in 5 s

Practice Questions

Q1
A train moving with a speed of 60 km/h applies brakes and comes to a stop in 5 seconds. What is the magnitude of its acceleration?
  1. -3 m/s²
  2. -2 m/s²
  3. -1 m/s²
  4. -4 m/s²

Questions & Step-by-Step Solutions

A train moving with a speed of 60 km/h applies brakes and comes to a stop in 5 seconds. What is the magnitude of its acceleration?
  • Step 1: Convert the speed from kilometers per hour (km/h) to meters per second (m/s). Use the conversion factor: 1 km/h = 1/3.6 m/s. So, 60 km/h = 60 / 3.6 = 16.67 m/s.
  • Step 2: Identify the initial velocity (u) and final velocity (v). The initial velocity (u) is 16.67 m/s (the speed of the train), and the final velocity (v) is 0 m/s (the train stops).
  • Step 3: Use the formula for acceleration (a): a = (v - u) / t, where t is the time taken to stop. Here, t = 5 seconds.
  • Step 4: Substitute the values into the formula: a = (0 - 16.67) / 5.
  • Step 5: Calculate the acceleration: a = -16.67 / 5 = -3.33 m/s².
  • Step 6: The magnitude of acceleration is the absolute value, which is approximately 3 m/s².
  • Speed Conversion – Understanding how to convert speed from km/h to m/s is essential for solving problems in physics.
  • Acceleration Calculation – Applying the formula for acceleration, which involves the change in velocity over time, is crucial for determining the correct answer.
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