What is the escape velocity for a satellite to leave the Earth's gravitational f

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Question: What is the escape velocity for a satellite to leave the Earth\'s gravitational field?

Options:

Correct Answer: 11.2 km/s

Solution:

The escape velocity from the Earth\'s surface is approximately 11.2 km/s.

What is the escape velocity for a satellite to leave the Earth's gravitational field?

What is the escape velocity for a satellite to leave the Earth's gravitational field?

Step 1: Understand what escape velocity means. It is the speed needed for an object to break free from a planet's gravitational pull without any additional propulsion.
Step 2: Know that the escape velocity from Earth is calculated using a specific formula that involves the mass of the Earth and the radius of the Earth.
Step 3: The formula for escape velocity (v) is v = sqrt(2 * G * M / R), where G is the gravitational constant, M is the mass of the Earth, and R is the radius of the Earth.
Step 4: When you plug in the values for G, M, and R, you find that the escape velocity from the Earth's surface is about 11.2 kilometers per second.
Step 5: Remember that this speed is necessary to leave the Earth's gravitational field without falling back.

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