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In a potentiometer experiment, if the balance point is found at 4 m with a 6 V b

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Question: In a potentiometer experiment, if the balance point is found at 4 m with a 6 V battery, what is the voltage across a 2 m length of the wire?

Options:

  1. 2 V
  2. 3 V
  3. 4 V
  4. 1 V

Correct Answer: 3 V

Solution:

The potential gradient is 6 V / 4 m = 1.5 V/m. Therefore, across 2 m, the voltage is 1.5 V/m * 2 m = 3 V.

In a potentiometer experiment, if the balance point is found at 4 m with a 6 V b

Practice Questions

Q1
In a potentiometer experiment, if the balance point is found at 4 m with a 6 V battery, what is the voltage across a 2 m length of the wire?
  1. 2 V
  2. 3 V
  3. 4 V
  4. 1 V

Questions & Step-by-Step Solutions

In a potentiometer experiment, if the balance point is found at 4 m with a 6 V battery, what is the voltage across a 2 m length of the wire?
  • Step 1: Identify the total voltage provided by the battery, which is 6 V.
  • Step 2: Identify the length of the wire where the balance point is found, which is 4 m.
  • Step 3: Calculate the potential gradient (voltage per meter) by dividing the total voltage by the length of the wire: 6 V / 4 m = 1.5 V/m.
  • Step 4: Determine the length of the wire segment for which you want to find the voltage, which is 2 m.
  • Step 5: Calculate the voltage across the 2 m length by multiplying the potential gradient by the length: 1.5 V/m * 2 m = 3 V.
  • Potential Gradient – The potential gradient is the change in voltage per unit length of the wire, calculated by dividing the total voltage by the length of the wire.
  • Voltage Calculation – The voltage across a specific length of wire can be determined by multiplying the potential gradient by that length.
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