In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in serie

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Question: In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in series, what is the current flowing through the circuit?

Options:

Correct Answer: 2 A

Solution:

Total resistance R = 8 + 16 = 24 ohms. Current I = V/R = 24V / 24Ω = 1 A.

In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in series, what is the current flowing through the circuit?

In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in series, what is the current flowing through the circuit?

Step 1: Identify the voltage of the battery, which is 24V.
Step 2: Identify the resistors in the circuit, which are 8 ohms and 16 ohms.
Step 3: Calculate the total resistance by adding the two resistors together: 8 ohms + 16 ohms = 24 ohms.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
Step 5: Substitute the values into the formula: I = 24V / 24 ohms.
Step 6: Calculate the current: 24V / 24 ohms = 1 A.

Ohm's Law – Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor.
Series Circuits – In a series circuit, the total resistance is the sum of the individual resistances, and the same current flows through all components.